(x^2-3x+4)(2x-1)=0

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Solution for (x^2-3x+4)(2x-1)=0 equation: 


Simplifying
(x2 + -3x + 4)(2x + -1) = 0

Reorder the terms:
(4 + -3x + x2)(2x + -1) = 0

Reorder the terms:
(4 + -3x + x2)(-1 + 2x) = 0

Multiply (4 + -3x + x2) * (-1 + 2x)
(4(-1 + 2x) + -3x * (-1 + 2x) + x2(-1 + 2x)) = 0
((-1 * 4 + 2x * 4) + -3x * (-1 + 2x) + x2(-1 + 2x)) = 0
((-4 + 8x) + -3x * (-1 + 2x) + x2(-1 + 2x)) = 0
(-4 + 8x + (-1 * -3x + 2x * -3x) + x2(-1 + 2x)) = 0
(-4 + 8x + (3x + -6x2) + x2(-1 + 2x)) = 0
(-4 + 8x + 3x + -6x2 + (-1 * x2 + 2x * x2)) = 0
(-4 + 8x + 3x + -6x2 + (-1x2 + 2x3)) = 0

Combine like terms: 8x + 3x = 11x
(-4 + 11x + -6x2 + -1x2 + 2x3) = 0

Combine like terms: -6x2 + -1x2 = -7x2
(-4 + 11x + -7x2 + 2x3) = 0

Solving
-4 + 11x + -7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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